ABC is a triangle in which angle C is a right | vedclass

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(B) Since $\angle C = 90^{\circ}$,the hypotenuse $AB$ must be the diameter of the circumcircle of $	riangle ABC$ because the angle subtended by the d

Vedclass · Accepted Answer

$x^2 + y^2 = 25$

Vedclass · Answer

(B) Since $\angle C = 90^{\circ}$,the hypotenuse $AB$ must be the diameter of the circumcircle of $	riangle ABC$ because the angle subtended by the diameter at the circumference is a right angle.The equation of a circle with diameter endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given by $(x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0$.Substituting the coordinates $A(-3, 4)$ and $B(3, -4)$:$(x - (-3))(x - 3) + (y - 4)(y - (-4)) = 0$$(x + 3)(x - 3) + (y - 4)(y + 4) = 0$$(x^2 - 9) + (y^2 - 16) = 0$$x^2 + y^2 - 25 = 0$$x^2 + y^2 = 25$.

$ABC$ is a triangle in which angle $C$ is a right angle. If the coordinates of $A$ and $B$ are $(-3, 4)$ and $(3, -4)$ respectively,then the equation of the circumcircle of triangle $ABC$ is

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