A team of 5 students is to be selected from 1 | vedclass

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(C) Since $2$ particular students are always to be included in the team,we have already selected $2$ members. Remaining members to be selected $= 5 -

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(C) Since $2$ particular students are always to be included in the team,we have already selected $2$ members. Remaining members to be selected $= 5 - 2 = 3$. Remaining students available to choose from $= 12 - 2 = 10$. Therefore,the number of ways to select the remaining $3$ students from $10$ available students is given by the combination formula ${}^{n}C_{r} = \frac{n!}{r!(n-r)!}$. Number of ways $= {}^{10}C_{3} = \frac{10 	imes 9 	imes 8}{3 	imes 2 	imes 1} = 10 	imes 3 	imes 4 = 120$.

$A$ team of $5$ students is to be selected from $12$ students. If two particular students are to be included in that team,then the number of ways that such team can be selected is

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