$\int_0^{\pi / 2} \frac{\sin ^3 x \cos x \, dx}{\sin ^4 x+\cos ^4 x} = ?$

  • A
    $\pi$
  • B
    $\frac{\pi}{2}$
  • C
    $\frac{\pi}{4}$
  • D
    $\frac{\pi}{8}$

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$\int_{0}^{\pi} \frac{x \, dx}{a^{2} \cos ^{2} x+b^{2} \sin ^{2} x}$ का मान ज्ञात कीजिए।

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माना $I=\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{1}{2-\cos 2 x}\left(\frac{3}{\pi}+\log \left(\frac{4+\sin x}{4-\sin x}\right)\right) d x$. दिया गया है कि $\int \frac{d x}{1+k x^2}=\frac{1}{\sqrt{k}} \tan ^{-1}(\sqrt{k} x)+c, \tan ^{-1}(0)=0$ और $\tan ^{-1}(\sqrt{3})=\frac{\pi}{3}$. तो $3 I^2=$

यदि $f(t) = \int_0^\pi \frac{2x \, dx}{1 - \cos^2 t \sin^2 x}$,जहाँ $0 < t < \pi$,तो $\int_0^{\frac{\pi}{2}} \frac{\pi^2 \, dt}{f(t)}$ का मान .......... है।

$\int_1^3 \frac{\log x^2}{\log \left(16 x^2-8 x^3+x^4\right)} d x=\ldots$

$\int_0^{\frac{\pi}{4}} \log (1+\tan x) \, dx =$

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