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(D) The current gain $\beta$ of a common-emitter transistor is defined as the ratio of the change in collector current $(\Delta i_C)$ to the change in

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$20 	ext{ mA}$

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(D) The current gain $\beta$ of a common-emitter transistor is defined as the ratio of the change in collector current $(\Delta i_C)$ to the change in base current $(\Delta i_B)$.$\beta = \frac{\Delta i_C}{\Delta i_B}$Given: $\beta = 80$ and $\Delta i_B = 250 \mu A = 250 	imes 10^{-6} 	ext{ A}$.Substituting the values into the formula:$80 = \frac{\Delta i_C}{250 	imes 10^{-6} 	ext{ A}}$$\Delta i_C = 80 	imes 250 	imes 10^{-6} 	ext{ A}$$\Delta i_C = 20,000 	imes 10^{-6} 	ext{ A}$$\Delta i_C = 20 	imes 10^{-3} 	ext{ A} = 20 	ext{ mA}$.Therefore,the change in collector current is $20 	ext{ mA}$.

$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. The change in collector current is:

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