A plane pi makes intercepts 3 and 4 respectiv | vedclass

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Question

(A) The intercept form of a plane is $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$,where $a, b, c$ are the intercepts on the $X, Y, Z$ axes respective

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$3x + 4z = 12$

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(A) The intercept form of a plane is $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$,where $a, b, c$ are the intercepts on the $X, Y, Z$ axes respectively.Given that the plane makes intercepts $4$ on the $X$-axis $(a=4)$ and $3$ on the $Z$-axis $(c=3)$.Since the plane is parallel to the $Y$-axis,the intercept on the $Y$-axis is infinite,which means $\frac{1}{b} = 0$.Substituting these values into the intercept form equation:$\frac{x}{4} + \frac{y}{\infty} + \frac{z}{3} = 1$$\frac{x}{4} + 0 + \frac{z}{3} = 1$Multiplying the entire equation by $12$ to clear the denominators:$3x + 4z = 12$.

$A$ plane $\pi$ makes intercepts $3$ and $4$ respectively on $Z$-axis and $X$-axis. If $\pi$ is parallel to $Y$-axis,then its equation is:

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