A manager decides to distribute Rs. 20000 bet | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the total amount be $S = 20000$. Let $X$ be the amount given to employee $X$ and $Y$ be the amount given to employee $Y$. Given $X + Y = 20000

Vedclass · Accepted Answer

$2/3$

Vedclass · Answer

(D) Let the total amount be $S = 20000$. Let $X$ be the amount given to employee $X$ and $Y$ be the amount given to employee $Y$. Given $X + Y = 20000$ and $X > Y$. Since $X$ is the bigger part,$X$ must be in the range $(10000, 20000]$. The total length of the sample space for $X$ is $20000 - 10000 = 10000$. We want the probability that $X \geq 2Y$. Substituting $Y = 20000 - X$,we get $X \geq 2(20000 - X)$. $X \geq 40000 - 2X \Rightarrow 3X \geq 40000 \Rightarrow X \geq 40000/3$. Since $X$ must be at most $20000$,the favorable range for $X$ is $[40000/3, 20000]$. The length of this interval is $20000 - 40000/3 = 20000/3$. The probability is $\frac{20000/3}{10000} = \frac{2}{3}$.

Similar Questions

$A$ fair coin is tossed repeatedly. If a tail appears on the first four tosses,then the probability of a head appearing on the fifth toss equals:

In a single throw of two dice,what is the probability of getting a total of $13$?

$A$ rational number is selected at random from the distinct rational numbers of the form $p/q$ formed with $p$ and $q$ belonging to the set $\{1, 2, 3, 4, 5, 6\}$. The probability that the rational number selected is a proper fraction is:

$A$ coin is tossed and a dice is rolled. The probability that the coin shows the head and the dice shows $6$ is

Suppose $3$ bulbs are selected at random from a lot. Each bulb is tested and classified as defective $(D)$ or non-defective $(N)$. Write the sample space of this experiment.

Vedclass Test Series

Exam Paper Generator

Online Exam Module