$A$ person is known to speak the truth in $3$ out of $4$ occasions. If he throws a die and reports that it is six,then the probability that it is actually six is

  • A
    $\frac{3}{8}$
  • B
    $\frac{2}{7}$
  • C
    $\frac{1}{9}$
  • D
    $\frac{4}{5}$

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