A cubic lattice has A atoms at the body centr | vedclass

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(C) atoms are at the body centre. Contribution $= 1 	imes 1 = 1$.$B$ atoms are at the corners. Contribution $= 8 	imes \frac{1}{8} = 1$.$C$ atoms ar

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$A_2 B_2 C_3$

Vedclass · Answer

(C) atoms are at the body centre. Contribution $= 1 	imes 1 = 1$.$B$ atoms are at the corners. Contribution $= 8 	imes \frac{1}{8} = 1$.$C$ atoms are at half of the face centres. Total face centres $= 6$,so $C$ atoms $= 3$. Contribution $= 3 	imes \frac{1}{2} = \frac{3}{2}$.The ratio of $A:B:C$ is $1:1:\frac{3}{2}$.Multiplying by $2$,we get $A_2 B_2 C_3$.Thus,the formula is $A_2 B_2 C_3$.

$A$ cubic lattice has $A$ atoms at the body centre,$B$ atoms at the corners,and $C$ atoms at half of the face centres. The formula of the lattice is:

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