A diatomic gas has an initial internal energy | vedclass

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(B) Initial internal energy,$U_i = 80 cal = 80 	imes 4.2 J = 336 J$. Work done on the gas,$W = -18 cal = -18 	imes 4.2 J = -75.6 J$ (Work done on th

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$369.6 J$

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(B) Initial internal energy,$U_i = 80 cal = 80 	imes 4.2 J = 336 J$. Work done on the gas,$W = -18 cal = -18 	imes 4.2 J = -75.6 J$ (Work done on the system is negative in the convention $\Delta Q = \Delta U + \Delta W$). Heat released by the gas,$Q = -42 J$ (Heat released is negative). According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$. $-42 = (U_f - 336) + (-75.6)$. $-42 = U_f - 336 - 75.6$. $-42 = U_f - 411.6$. $U_f = 411.6 - 42 = 369.6 J$.

$A$ diatomic gas has an initial internal energy of $80 cal$. $A$ work of $18 cal$ is done on the gas and the gas releases heat energy of $42 J$. The final internal energy of the gas is

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