A vessel contains 3 moles of He,1 mole of Ar, | vedclass

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(B) The internal energy $U$ of $n$ moles of a gas is given by $U = n \frac{f}{2} RT$,where $f$ is the degree of freedom.For monoatomic gases $(He, Ar)

Vedclass · Accepted Answer

$26$

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(B) The internal energy $U$ of $n$ moles of a gas is given by $U = n \frac{f}{2} RT$,where $f$ is the degree of freedom.For monoatomic gases $(He, Ar)$,$f = 3$.For diatomic gases $(N_2, H_2)$,$f = 5$ (ignoring vibrational modes).Total internal energy $U_{total} = U_{He} + U_{Ar} + U_{N_2} + U_{H_2}$.$U_{total} = (3 	imes \frac{3}{2} RT) + (1 	imes \frac{3}{2} RT) + (5 	imes \frac{5}{2} RT) + (3 	imes \frac{5}{2} RT)$.$U_{total} = (4.5 + 1.5 + 12.5 + 7.5) RT = 26 RT$.

$A$ vessel contains $3$ moles of $He$,$1$ mole of $Ar$,$5$ moles of $N_2$,and $3$ moles of $H_2$. If the vibrational modes are ignored,the total internal energy of the system of gases is (in $RT$)

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