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(A) The angular width of the diffraction fringe is given by the formula $	heta = \frac{\lambda}{a}$,where $\lambda$ is the wavelength of light and $a

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bands will be narrower

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(A) The angular width of the diffraction fringe is given by the formula $	heta = \frac{\lambda}{a}$,where $\lambda$ is the wavelength of light and $a$ is the slit width. Similarly,the linear width of the central maximum is given by $\beta = \frac{2D\lambda}{a}$. From these relations,it is clear that the width of the diffraction bands is directly proportional to the wavelength of the light used,i.e.,$\beta \propto \lambda$. Since the wavelength of blue light is smaller than the wavelength of red light $(\lambda_{	ext{blue}} Therefore,the bands will become narrower.

$A$ diffraction pattern is obtained by using a beam of red light. If the red light is replaced by blue light,then:

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