Class 12PhysicsWave OpticsFresnel distance, Diffraction through circular slit, concept of Airy Disc, Rayleigh Criterion of Resolution , Fraunhofer diffraction
Medium$A$ Fraunhofer diffraction pattern due to a narrow slit is obtained on a screen placed at a distance $D$ from the slit whose slit width is $a$. The distance of the first secondary maximum from the central maximum is
- A$\frac{3 D \lambda}{a}$
- B$\frac{3 D \lambda}{2 a}$
- C$\frac{2 D \lambda}{3 a}$
- D$\frac{2 D \lambda}{a}$
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If the slit width is $2 \, mm$ and the wavelength of light used is $4000 \, Å$, then the Fresnel distance is nearly:
$A$ converging lens of a telescope with a diameter of $5 \text{ cm}$ has a focal length of $25 \text{ cm}$. In the focal plane of the lens, the distance between the centres of the Fraunhofer diffraction pattern is (wavelength of light used = $5000 \text{ Å}$, Rayleigh's criterion is satisfied).
DifficultMHT CET 2026
View SolutionIn Fresnel diffraction,if the distance between the disc and the screen is decreased,the intensity of the central bright spot will
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View Solution$A$ light beam of wavelength $800 \,nm$ passes through a single slit and is projected on a screen kept at $5 \,m$ away from the slit. What should be the slit width for the ray optics approximation to be valid (in $\,mm$)?
For Fraunhofer diffraction to occur:
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