(B) The fringe width $\beta$ in a medium with refractive index $\mu$ is given by the formula: $\beta = \frac{\lambda' D}{d}$,where $\lambda' = \frac{\

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(B) The fringe width $\beta$ in a medium with refractive index $\mu$ is given by the formula: $\beta = \frac{\lambda' D}{d}$,where $\lambda' = \frac{\lambda}{\mu}$.Thus,$\beta = \frac{\lambda D}{\mu d}$.Given values:$\lambda = 6300 \ \mathring{A} = 6300 \times 10^{-10} \ m$$D = 1.33 \ m$$d = 1 \ mm = 10^{-3} \ m$$\mu = 1.33$Substituting these values into the formula:$\beta = \frac{6300 \times 10^{-10} \times 1.33}{1.33 \times 10^{-3}}$$\beta = 6300 \times 10^{-7} \ m$$\beta = 6.3 \times 10^{-4} \ m = 0.63 \ mm$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

Medium

$A$ Young's double-slit experimental setup is immersed in water of refractive index $1.33$. It has a slit separation of $1 \ mm$ and the distance between the slits and the screen is $1.33 \ m$. If the wavelength of incident light on the slits is $6300 \ \mathring{A}$,then the fringe width on the screen is:

AP EAMCET 2019 All AP EAMCET

A
$6.3 \ mm$
B
$0.63 \ mm$
C
$0.63 \ m$
D
$6.3 \ m$

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Class 12

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Wave Optics

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Young's Double Slit Experiment (YDSE)

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Two parallel slits $0.6 \,mm$ apart are illuminated by a light source of wavelength $6000 \,\mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \,m$ away from the slits is:

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In Young's double slit experiment,the light emitted from the source has $\lambda = 6.5 \times 10^{-7} \, m$ and the distance between the two slits is $1 \, mm$. The distance between the screen and the slits is $1 \, m$. The distance between the third dark fringe and the fifth bright fringe will be ......... $mm$.

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Using Young's double slit experiment,a monochromatic light of wavelength $5000 \,\mathring A$ produces fringes of fringe width $0.5 \,mm$. If another monochromatic light of wavelength $6000 \,\mathring A$ is used and the separation between the slits is doubled,then the new fringe width will be ............... $mm$.

DifficultJEE MAIN 2022

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Light of wavelength $520\, nm$ passing through a double slit produces an interference pattern of relative intensity versus deflection angle $\theta$ as shown in the figure. The separation $d$ between the slits is

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Using monochromatic light of wavelength $\lambda$,an experimentalist sets up the Young's double slit experiment in three ways as shown. If she observes that $y = \beta'$,the wavelength of light used is.....$nm$

DifficultJEE MAIN 2014

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Two parallel slits $0.6 \,mm$ apart are illuminated by a light source of wavelength $6000 \,\mathring{A}$. The distance between two consecutive dark fringes on a screen $1 \,m$ away from the slits is:

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