$A$ uniform chain of mass $M$ and length $L$ is lying on a smooth horizontal table,with half of its length hanging down. The work done in pulling the entire chain up onto the table is

  • A
    $\frac{M g L}{2}$
  • B
    $\frac{M g L}{4}$
  • C
    $\frac{M g L}{8}$
  • D
    $\frac{M g L}{16}$

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