$(CH_3)_3CH$ $\xrightarrow{KMnO_4} X$ $\xrightarrow[573 \ K]{Cu} Y$
The number of $sp^3$ and $sp^2$ carbons in $Y$ are respectively

  • A
    $3, 1$
  • B
    $1, 3$
  • C
    $2, 2$
  • D
    $4, 0$

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$CH_2=CH-CH_2-CH_2-C(OH)(CH_2OH)-CH_2-CH_3$ $\xrightarrow[TsOH]{(CH_3)_2CO}$ $(A)$ $\xrightarrow[{(CH_3)_2S}]{O_3}$ $(B) + HCHO$. Product $(B)$ is

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Which reagent converts propene into $1$-propanol?

Which of the following is Baeyer's reagent?

Consider the following reaction sequence:
$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$
The major end product formed is:

Addition of $HBr$ to propene yields $2-$bromopropane,while in the presence of benzoyl peroxide,the same reaction yields $1-$bromopropane. Explain and give the mechanism.

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