A solid cylinder of mass 2 kg,length 40 cm | vedclass

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(C) Let the centre of the sphere be the origin $(0, 0)$.The radius of the sphere is $R_s = 10 \ cm$.The sphere is in contact with the cylinder,so the

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$24$

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(C) Let the centre of the sphere be the origin $(0, 0)$.The radius of the sphere is $R_s = 10 \ cm$.The sphere is in contact with the cylinder,so the centre of the cylinder is at a distance of $R_s + L/2$ from the centre of the sphere,where $L = 40 \ cm$ is the length of the cylinder.Distance of the centre of the cylinder from the centre of the sphere,$x_c = 10 \ cm + 20 \ cm = 30 \ cm$.Mass of the sphere,$m_s = 0.5 \ kg$.Mass of the cylinder,$m_c = 2 \ kg$.The centre of mass $X_{cm}$ of the system from the centre of the sphere is given by:$X_{cm} = \frac{m_s \cdot x_s + m_c \cdot x_c}{m_s + m_c}$$X_{cm} = \frac{0.5 \cdot 0 + 2 \cdot 30}{0.5 + 2}$$X_{cm} = \frac{60}{2.5} = 24 \ cm$.

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