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(A) The reaction is: $NH_2CONH_2 + 2 H_2O \rightarrow (NH_4)_2CO_3 \rightleftharpoons 2 NH_3 + H_2O + CO_2$.Here,$[X]$ is ammonium carbonate $(NH_4)_2

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$sp^2, sp$

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(A) The reaction is: $NH_2CONH_2 + 2 H_2O \rightarrow (NH_4)_2CO_3 \rightleftharpoons 2 NH_3 + H_2O + CO_2$.Here,$[X]$ is ammonium carbonate $(NH_4)_2CO_3$ and $[Y]$ is carbon dioxide $(CO_2)$.In the carbonate ion $(CO_3^{2-})$,the carbon atom is bonded to three oxygen atoms with one double bond and two single bonds,resulting in $sp^2$ hybridization.In the carbon dioxide molecule $(O=C=O)$,the carbon atom is bonded to two oxygen atoms with two double bonds,resulting in $sp$ hybridization.Therefore,the hybridization of carbon in $X$ and $Y$ is $sp^2$ and $sp$ respectively.

$NH_2CONH_2 + 2 H_2O \rightarrow [X] \rightleftharpoons 2 NH_3 + H_2O + [Y]$
The hybridization of carbon in $X$ and $Y$ respectively are

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$NH_2CONH_2 + 2 H_2O \rightarrow [X] \rightleftharpoons 2 NH_3 + H_2O + [Y]$The hybridization of carbon in $X$ and $Y$ respectively are