A message signal of frequency 15 kHz is used | vedclass

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Question

(B) The frequencies of the side bands in amplitude modulation are given by the carrier frequency $
u_c$ plus and minus the message signal frequency $

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(B) The frequencies of the side bands in amplitude modulation are given by the carrier frequency $
u_c$ plus and minus the message signal frequency $f_m$. Given: $f_m = 15 kHz$,Upper Side Band $(USB)$ $= 1515 kHz$,Lower Side Band $(LSB)$ $= 1485 kHz$. The side bands are $
u_c + f_m$ and $
u_c - f_m$. Therefore,$
u_c + 15 kHz = 1515 kHz$ or $
u_c - 15 kHz = 1485 kHz$. Solving for $
u_c$: $
u_c = 1515 kHz - 15 kHz = 1500 kHz$. Converting to $MHz$: $1500 kHz = 1.5 MHz$.

$A$ message signal of frequency $15 kHz$ is used to modulate a carrier of frequency $v_c$. If the side bands produced are $1515 kHz$ and $1485 kHz$,then $v_c$ is (in $MHz$)

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