A TV transmission antenna is 40 m tall. How | vedclass

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(B) The range $(d)$ of a $TV$ transmission antenna of height $h$ is given by the formula: $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Given:

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$512 \pi 	imes 10^6 \ m^2$

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(B) The range $(d)$ of a $TV$ transmission antenna of height $h$ is given by the formula: $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Given: $h = 40 \ m$ and $R = 6400 \ km = 6400 	imes 10^3 \ m$.The service area covered by the antenna is the area of a circle with radius $d$,given by: $Area = \pi d^2$.Substituting the value of $d^2 = 2hR$ into the area formula:$Area = \pi (2hR)$$Area = \pi 	imes 2 	imes 40 	imes (6400 	imes 10^3)$$Area = \pi 	imes 80 	imes 6400 	imes 10^3$$Area = 512000 	imes 10^3 \pi \ m^2$$Area = 512 	imes 10^6 \pi \ m^2$.

$A$ $TV$ transmission antenna is $40 \ m$ tall. How much service area can it cover if the receiving antenna is at the ground level? (Radius of the Earth $= 6400 \ km$)

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