A circular coil of area 200 ~cm^2 and 50 turn | vedclass

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(B) The maximum induced electromotive force $(emf)$ in a rotating coil is given by the formula: $e_{\max} = N B A \omega$. Given: Number of turns $(N)

Vedclass · Accepted Answer

$0.8$

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(B) The maximum induced electromotive force $(emf)$ in a rotating coil is given by the formula: $e_{\max} = N B A \omega$. Given: Number of turns $(N)$ = $50$ Magnetic field $(B)$ = $2 	imes 10^{-2} ~T$ Area $(A)$ = $200 ~cm^2 = 200 	imes 10^{-4} ~m^2 = 2 	imes 10^{-2} ~m^2$ Angular speed $(\omega)$ = $40 ~rad/s$ Substituting these values into the formula: $e_{\max} = 50 	imes (2 	imes 10^{-2}) 	imes (2 	imes 10^{-2}) 	imes 40$ $e_{\max} = 50 	imes 4 	imes 10^{-4} 	imes 40$ $e_{\max} = 200 	imes 40 	imes 10^{-4}$ $e_{\max} = 8000 	imes 10^{-4} = 0.8 ~V$ Thus,the maximum induced $emf$ is $0.8 ~V$.

$A$ circular coil of area $200 ~cm^2$ and $50$ turns is rotating about its vertical diameter with an angular speed of $40 ~rad/s$ in a uniform horizontal magnetic field of magnitude $2 \times 10^{-2} ~T$. The maximum emf induced in the coil is (in $~V$)

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