frac{1-cos 2 theta+sin 2 theta}{1+cos 2 theta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.S

Vedclass · Accepted Answer

$	an 	heta$

Vedclass · Answer

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.Substituting these into the expression:$\frac{1 - (1 - 2 \sin^2 	heta) + 2 \sin 	heta \cos 	heta}{1 + (2 \cos^2 	heta - 1) + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin^2 	heta + 2 \sin 	heta \cos 	heta}{2 \cos^2 	heta + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin 	heta (\sin 	heta + \cos 	heta)}{2 \cos 	heta (\cos 	heta + \sin 	heta)}$$= \frac{\sin 	heta}{\cos 	heta} = 	an 	heta$.

$\frac{1-\cos 2 \theta+\sin 2 \theta}{1+\cos 2 \theta+\sin 2 \theta}=$

Similar Questions

If $\tan x + \tan \left(x + \frac{\pi}{3}\right) + \tan \left(x + \frac{2\pi}{3}\right) = 3$,then $\tan 3x$ is equal to

If $\tan \alpha = \frac{1}{7}$ and $\sin \beta = \frac{1}{\sqrt{10}}$ where $0 < \alpha, \beta < \frac{\pi}{2}$,then $2\beta$ is equal to

$\frac{1 + \sin A - \cos A}{1 + \sin A + \cos A} = $

$\tan A + 2 \tan 2A + 4 \tan 4A + 8 \cot 8A = $

If $\tan x + \tan \left( \frac{\pi}{3} + x \right) + \tan \left( \frac{2\pi}{3} + x \right) = 3$,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module