$\int_0^\pi \frac{x \, dx}{4 \cos^2 x + 9 \sin^2 x} = $

  • A
    $\frac{\pi^2}{12}$
  • B
    $\frac{\pi^2}{4}$
  • C
    $\frac{\pi^2}{6}$
  • D
    $\frac{\pi^2}{3}$

Explore More

Similar Questions

$0 \le x \le \frac{\pi}{2}$ માટે,$\int_{0}^{\sin^{2}x} \sin^{-1}(\sqrt{t}) \, dt + \int_{0}^{\cos^{2}x} \cos^{-1}(\sqrt{t}) \, dt$ ની કિંમત શોધો.

નિશ્ચિત સંકલનના ગુણધર્મોનો ઉપયોગ કરીને,$\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sin ^{2} x \, dx$ નું મૂલ્ય શોધો.

$\int_{0}^{\pi} \frac{x \sin x}{1+\cos ^{2} x} d x$ ની કિંમત શોધો.

$\int_{-1}^1 \frac{\log 2 - \log(1+x)}{\sqrt{1-x^2}} dx =$

$\int_0^{\pi /2} \frac{\cos x}{1 + \cos x + \sin x} \,dx = $

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo