A straight wire of length 20 text{ cm} carryi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Length of wire $L = 20 	ext{ cm} = 0.2 	ext{ m}$, Current $I = \frac{3}{\pi^2} 	ext{ A}$.When the wire is bent into a circle, its length

Vedclass · Accepted Answer

$6 	imes 10^{-6} 	ext{ T}$

Vedclass · Answer

(D) Given: Length of wire $L = 20 	ext{ cm} = 0.2 	ext{ m}$, Current $I = \frac{3}{\pi^2} 	ext{ A}$.When the wire is bent into a circle, its length becomes the circumference of the circle: $L = 2 \pi R$.$20 	imes 10^{-2} = 2 \pi R \Rightarrow R = \frac{10^{-1}}{\pi} 	ext{ m}$.The magnetic field $B$ at the centre of a circular loop is given by $B = \frac{\mu_0 I}{2R}$.Substituting the values: $B = \frac{(4 \pi 	imes 10^{-7}) 	imes (\frac{3}{\pi^2})}{2 	imes (\frac{10^{-1}}{\pi})}$.$B = \frac{4 \pi 	imes 10^{-7} 	imes 3}{2 	imes 10^{-1} 	imes \pi} = \frac{12 \pi 	imes 10^{-7}}{2 \pi 	imes 10^{-1}} = 6 	imes 10^{-6} 	ext{ T}$.

$A$ straight wire of length $20 \text{ cm}$ carrying a current of $\frac{3}{\pi^2} \text{ A}$ is bent in the form of a circle. The magnetic field at the centre of the circle is

Similar Questions

The $SI$ unit of magnetic permeability is

Two insulated circular loops $A$ and $B$ of radius '$a$' carry a current of '$I$' in the directions as shown in the figure. The magnitude of the magnetic induction at the centre $O$ will be:

Surface charge density on a ring of radius $a$ and width $d$ is $\sigma$ as shown in the figure. It rotates with frequency $f$ about its own axis. Assume that the charge is only on the outer surface. The magnetic field induction at the centre is (Assume that $d \ll a$):

Two long parallel wires are at a distance $2d$ apart. They carry steady equal currents flowing out of the plane of the paper,as shown. The variation of the magnetic field $B$ along the line $XX'$ is given by

The magnetic field $d\overrightarrow{B}$ due to a small current element $d\overrightarrow{l}$ at a distance $\overrightarrow{r}$ from an element carrying current $i$ is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module