(C) The mean radius $r_m$ of the toroid is calculated as: $r_m = \frac{0.24 + 0.26}{2} = 0.25 \ m$ The magnetic field $B$ inside a toroid is given by

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(C) The mean radius $r_m$ of the toroid is calculated as: $r_m = \frac{0.24 + 0.26}{2} = 0.25 \ m$ The magnetic field $B$ inside a toroid is given by the formula: $B = \mu_0 n I = \frac{\mu_0 N I}{2 \pi r_m}$ Substituting the given values: $N = 2500$, $I = 10 \ A$, $r_m = 0.25 \ m$, and $\mu_0 = 4 \pi \times 10^{-7} \ T \cdot m/A$ $B = \frac{4 \pi \times 10^{-7} \times 2500 \times 10}{2 \pi \times 0.25}$ $B = \frac{2 \times 10^{-7} \times 25000}{0.25} = \frac{5 \times 10^{-3}}{0.25} = 20 \times 10^{-3} = 2 \times 10^{-2} \ T$

Class 12 Physics Moving Charges and Magnetism Ampere’s circuital law and its application (Solenoid and Toroid)

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$A$ toroid core has an inner radius of $0.24 \ m$ and an outer radius of $0.26 \ m$. $A$ current of $10 \ A$ flows through the wire having $2500$ turns around it. Find the magnetic field inside the core of the toroid.

TS EAMCET 2022 All TS EAMCET

A
$\pi \times 10^{-2} \ T$
B
$2 \pi \times 10^{-2} \ T$
C
$2 \times 10^{-2} \ T$
D
$20 \times 10^{-2} \ T$

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Moving Charges and Magnetism

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Ampere’s circuital law and its application (Solenoid and Toroid)

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$A$ coil wrapped around a toroid has an inner radius of $20 \,cm$ and an outer radius of $25 \,cm$. If the wire wrapping makes $800$ turns and carries a current of $12 \,A$, the maximum and minimum values of the magnetic field within the toroid are:

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$A$ $90\, cm$ long solenoid has six layers of windings of $450\, turns$ each. If the diameter of the solenoid is $2.2\, cm$ and the current carried is $6\, A$, then the magnitude of the magnetic field inside the solenoid, near its centre is: (in $\pi\, G$)

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$A$ toroid core has an inner radius of $0.24 \ m$ and an outer radius of $0.26 \ m$. $A$ current of $10 \ A$ flows through the wire having $2500$ turns around it. Find the magnetic field inside the core of the toroid.

Similar Questions

$A$ coil wrapped around a toroid has an inner radius of $20 \,cm$ and an outer radius of $25 \,cm$. If the wire wrapping makes $800$ turns and carries a current of $12 \,A$, the maximum and minimum values of the magnetic field within the toroid are:

If the number of turns per unit length of a solenoid is doubled, what happens to the magnetic field in the solenoid?

There is a long cylindrical pipe wire of internal radius $r$ and external radius $R$ carrying current $i$ along its length. The variation of magnetic field with distance from the axis of the wire can be represented by the :-

The number of turns per unit length of a long solenoid is $10 \, \text{turns/cm}$. If its average radius is $5 \, \text{cm}$ and it carries a current of $10 \, \text{A}$, then the ratio of flux densities obtained at the centre and at the end on the axis will be:

$A$ $90\, cm$ long solenoid has six layers of windings of $450\, turns$ each. If the diameter of the solenoid is $2.2\, cm$ and the current carried is $6\, A$, then the magnitude of the magnetic field inside the solenoid, near its centre is: (in $\pi\, G$)

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