$A$ metal cube of side $10 \,cm$ rests on a film of a liquid of thickness $0.2 \,mm$. If upon applying a horizontal force $\overrightarrow{F}$ of magnitude $0.1 \,N$ the cube slides with a constant speed of $0.08 \,m/s$, then the coefficient of viscosity is

  • A
    $2.5 \times 10^{-2} \frac{Ns}{m^2}$
  • B
    $0.25 \times 10^{-2} \frac{Ns}{m^2}$
  • C
    $5 \times 10^{-2} \frac{Ns}{m^2}$
  • D
    $0.5 \times 10^{-2} \frac{Ns}{m^2}$

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