A planet is revolving around the Sun in an el | vedclass

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(A) According to Kepler's Second Law (Law of Areas), the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of tim

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The time taken in travelling $DAB$ is less than that for $BCD$.

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(A) According to Kepler's Second Law (Law of Areas), the radius vector joining the Sun and the planet sweeps out equal areas in equal intervals of time.In the given figure, the Sun $(S)$ is at one of the foci of the elliptical orbit.The area swept by the planet in path $DAB$ is the area of the region bounded by the arc $DAB$ and the lines $SD$ and $SB$.The area swept by the planet in path $BCD$ is the area of the region bounded by the arc $BCD$ and the lines $SB$ and $SD$.Since the Sun is closer to the side $A$, the area swept by the planet in path $DAB$ is smaller than the area swept in path $BCD$.Therefore, the time taken to travel $DAB$ is less than the time taken to travel $BCD$.

$A$ planet is revolving around the Sun in an elliptical orbit as shown in the figure. Which of the following is a correct statement?

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