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(A) Let the length of each step be $d$. The initial position is $(0, 0)$.$1$. Moves $2$ steps East: Position becomes $(2d, 0)$.$2$. Turns right (South

Vedclass · Accepted Answer

North-West

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(A) Let the length of each step be $d$. The initial position is $(0, 0)$.$1$. Moves $2$ steps East: Position becomes $(2d, 0)$.$2$. Turns right (South) and moves $4$ steps: Position becomes $(2d, -4d)$.$3$. Turns right (West) and moves $6$ steps: Position becomes $(2d - 6d, -4d) = (-4d, -4d)$.$4$. Turns right (North) and moves the remaining steps. Total steps taken so far $= 2 + 4 + 6 = 12$. Remaining steps $= 20 - 12 = 8$ steps North.Final position $= (-4d, -4d + 8d) = (-4d, 4d)$.The final position is in the second quadrant (West and North). Since the $x$ and $y$ coordinates have equal magnitude $(|-4d| = |4d|)$, the position is exactly at an angle of $45^{\circ}$ North of West, which is North-West.

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