$A$ man of mass $80 \ kg$ goes to the market on a scooter of mass $100 \ kg$ with a certain speed. On application of brakes, the stopping distance is $S_1$. The man returns home on the same scooter, with the same speed with a $60 \ kg$ bag of rice. If $S_2$ is the new stopping distance when the brakes are applied with the same force, then:

  • A
    $7 S_1 = 4 S_2$
  • B
    $2 S_1 = S_2$
  • C
    $3 S_1 = 4 S_2$
  • D
    $4 S_1 = 3 S_2$

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