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Question

(D) Given that the body starts from rest, so initial velocity $u = 0$. Let the uniform acceleration be $a$. The velocity after $n$ seconds is given by

Vedclass · Accepted Answer

$\frac{2V(n-1)}{n}$

Vedclass · Answer

(D) Given that the body starts from rest, so initial velocity $u = 0$. Let the uniform acceleration be $a$. The velocity after $n$ seconds is given by $v = u + at$. Substituting the values, $V = 0 + a(n)$, which gives $a = \frac{V}{n}$. The displacement $S$ in the last $t = 2 	ext{ s}$ can be calculated using the formula $S = v_{final}t - \frac{1}{2}at^2$, where $v_{final} = V$. $S = V(2) - \frac{1}{2} \left(\frac{V}{n}ight)(2)^2$. $S = 2V - \frac{1}{2} \left(\frac{V}{n}ight)(4)$. $S = 2V - \frac{2V}{n}$. $S = 2V \left(1 - \frac{1}{n}ight) = \frac{2V(n-1)}{n}$.

$A$ body starts from rest with uniform acceleration. If its velocity after $n^{\text{th}}$ second (last second) is $V$, then its displacement in the last two seconds is

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