A bomb is dropped on an enemy post on the gro | vedclass

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(B) Given: Velocity of the aeroplane, $u = 60 \ km/h = 60 	imes \frac{5}{18} \ m/s = \frac{50}{3} \ m/s$.Height of the aeroplane, $h = 490 \ m$.Accel

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$\left(\frac{500}{3}\right) \ m$

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(B) Given: Velocity of the aeroplane, $u = 60 \ km/h = 60 	imes \frac{5}{18} \ m/s = \frac{50}{3} \ m/s$.Height of the aeroplane, $h = 490 \ m$.Acceleration due to gravity, $g = 9.8 \ m/s^2$.The time taken by the bomb to reach the ground is given by $h = \frac{1}{2}gt^2$, so $t = \sqrt{\frac{2h}{g}}$.$t = \sqrt{\frac{2 	imes 490}{9.8}} = \sqrt{\frac{980}{9.8}} = \sqrt{100} = 10 \ s$.The horizontal distance covered by the bomb in this time is $R = u 	imes t$.$R = \left(\frac{50}{3}ight) 	imes 10 = \frac{500}{3} \ m$.

$A$ bomb is dropped on an enemy post on the ground by an aeroplane flying horizontally with a velocity of $60 \ km/h$ at a height of $490 \ m$. At the time of dropping the bomb, the horizontal distance of the aeroplane from the enemy post so that the bomb hits the target is

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