$A$ rod of length $L$ and negligible mass is suspended by two identical strings $AB$ and $CD$ as shown in the figure. $A$ mass $M$ is suspended from point $O$ which is at a distance $x$ from $B$. If the frequency of the first harmonic of $AB$ is equal to the frequency of the second harmonic of $CD$, then the value of $x$ is

  • A
    $\frac{L}{5}$
  • B
    $\frac{2L}{7}$
  • C
    $\frac{3L}{10}$
  • D
    $\frac{L}{9}$

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