A metal cube absorbs 2100.0 J of heat when i | vedclass

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(A) The heat absorbed by a substance is given by the formula: $H = m s \Delta T$, where $H$ is the heat, $m$ is the mass, $s$ is the specific heat cap

Vedclass · Accepted Answer

$1.16$

Vedclass · Answer

(A) The heat absorbed by a substance is given by the formula: $H = m s \Delta T$, where $H$ is the heat, $m$ is the mass, $s$ is the specific heat capacity, and $\Delta T$ is the change in temperature.Given values are: $H = 2100.0 \ J$, $s = 900 \ J \ kg^{-1} K^{-1}$, and $\Delta T = 2^{\circ} C = 2 \ K$.Rearranging the formula to solve for mass $m$: $m = \frac{H}{s \Delta T}$.Substituting the values: $m = \frac{2100}{900 	imes 2} = \frac{2100}{1800} = 1.166... \ kg$.Rounding to two decimal places, we get $m \approx 1.16 \ kg$.

$A$ metal cube absorbs $2100.0 \ J$ of heat when its temperature is raised by $2^{\circ} C$. If the specific heat of the metal is $900 \ J \ kg^{-1} K^{-1}$, then the mass of the cube is (in $kg$)

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