176 text{ grams} of CO_2 can change its tempe | vedclass

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(A) The formula for heat absorbed is given by $\Delta Q = n C \Delta T$, where $n$ is the number of moles, $C$ is the molar specific heat, and $\Delta

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$30$

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(A) The formula for heat absorbed is given by $\Delta Q = n C \Delta T$, where $n$ is the number of moles, $C$ is the molar specific heat, and $\Delta T$ is the change in temperature.First, calculate the number of moles $n$ of $CO_2$:$n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{176 	ext{ g}}{44 	ext{ g/mol}} = 4 	ext{ moles}$.Given $\Delta Q = 3600 	ext{ J}$ and $\Delta T = 30^{\circ} C - 0^{\circ} C = 30 	ext{ K}$.Substituting these values into the equation:$3600 = 4 	imes C 	imes 30$$3600 = 120 	imes C$$C = \frac{3600}{120} = 30 	ext{ J mol}^{-1} K^{-1}$.

$176 \text{ grams}$ of $CO_2$ can change its temperature from $0^{\circ} C$ to $30^{\circ} C$ by absorbing $3600 \text{ joules}$ of thermal energy. The molar specific heat of $CO_2$ in $J \ mol^{-1} K^{-1}$ is:

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