A 500 Omega resistor connected to an external | vedclass

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(C) Since the temperature of the gas remains constant, the heat supplied by the resistor is equal to the work done by the gas on the piston.Heat dissi

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$20$

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(C) Since the temperature of the gas remains constant, the heat supplied by the resistor is equal to the work done by the gas on the piston.Heat dissipated by the resistor in time $t$ is $H = i^2 R t$.Work done by the gas on the piston is $W = F \Delta x$, where $F = mg$ is the force exerted by the piston and $\Delta x$ is the displacement.Equating heat and work: $i^2 R t = (mg) \Delta x$.Rearranging for the velocity of the piston $v = \frac{\Delta x}{t} = \frac{i^2 R}{mg}$.Given $i = 200 	ext{ mA} = 0.2 	ext{ A}$, $R = 500 \Omega$, $m = 10 	ext{ kg}$, and $g = 10 	ext{ m/s}^2$.$v = \frac{(0.2)^2 	imes 500}{10 	imes 10} = \frac{0.04 	imes 500}{100} = \frac{20}{100} = 0.2 	ext{ m/s}$.Converting to $	ext{cm/s}$, $v = 0.2 	imes 100 	ext{ cm/s} = 20 	ext{ cm/s}$.

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