AB is an ionic solid. The ionic radii of A^{+ | vedclass

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(D) The lattice energy $(U)$ of an ionic crystal is defined as the energy released when gaseous ions combine to form one mole of the solid ionic cryst

Vedclass · Accepted Answer

$\frac{1}{(r_c + r_a)}$

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(D) The lattice energy $(U)$ of an ionic crystal is defined as the energy released when gaseous ions combine to form one mole of the solid ionic crystal.According to the Born-Landé equation, the lattice energy is inversely proportional to the inter-ionic distance $(r_0)$.Since the inter-ionic distance $r_0$ is the sum of the ionic radii of the cation $(r_c)$ and the anion $(r_a)$, we have $r_0 = r_c + r_a$.Therefore, the lattice energy $U$ is proportional to $\frac{1}{(r_c + r_a)}$.

$AB$ is an ionic solid. The ionic radii of $A^{+}$ and $B^{-}$ are respectively $r_c$ and $r_a$. Lattice energy of $AB$ is proportional to:

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