$A$ car travelling at a speed of $54 \ km/h$ towards a wall sounds a horn of frequency $400 \ Hz$. The difference in the frequencies of two sounds, one received directly from the car and the other reflected from the wall, noticed by a person standing between the car and the wall is (speed of sound in air is $335 \ m/s$):

  • A
    $35.9 \ Hz$
  • B
    $20 \ Hz$
  • C
    $70 \ Hz$
  • D
    $35.9 \ Hz$ (Wait, let's calculate: $v_s = 54 \ km/h = 15 \ m/s$, $v = 335 \ m/s$, $f = 400 \ Hz$. Direct sound frequency $f_1 = f = 400 \ Hz$. Reflected sound frequency $f_2 = f \times \frac{v}{v - v_s} = 400 \times \frac{335}{335 - 15} = 400 \times \frac{335}{320} = 418.75 \ Hz$. Difference $= 418.75 - 400 = 18.75 \ Hz$. Since $18.75 \ Hz$ is not in options, let's re-evaluate. If the observer is between the car and wall, the direct sound is $f_1 = f \times \frac{v}{v - v_s}$ and reflected is $f_2 = f \times \frac{v}{v - v_s}$. The difference is zero. Wait, the observer is stationary. Direct sound $f_1 = f \times \frac{v}{v - v_s}$. Reflected sound $f_2 = f \times \frac{v}{v - v_s}$. The difference is $0$. Let's re-read: 'person standing between the car and the wall'. The car is moving towards the wall. The person hears direct sound from the car (source moving towards observer) and reflected sound from the wall (wall acts as a source moving towards observer). Both frequencies are the same. Difference is Zero.

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Similar Questions

$A$ source of sound is moving with a constant velocity of $20\, m/s$ emitting a note of frequency $1000\, Hz.$ The ratio of frequencies observed by a stationary observer while the source is approaching him and after it crosses him will be (Speed of sound $v = 340\, m/s$).

Two men are walking along a horizontal straight line in the same direction. The man in front walks at a speed $1.0 \ m \ s^{-1}$ and the man behind walks at a speed $2.0 \ m \ s^{-1}$. $A$ third man is standing at a height $12 \ m$ above the same horizontal line such that all three men are in a vertical plane. The two walking men are blowing identical whistles which emit a sound of frequency $1430 \ Hz$. The speed of sound in air is $330 \ m \ s^{-1}$. At the instant when the moving men are $10 \ m$ apart,the stationary man is equidistant from them. The frequency of beats in $Hz$ heard by the stationary man at this instant is:

$A$ car is moving at a velocity of $17 \ m/s$ towards an approaching bus that blows a horn at a frequency of $640 \ Hz$ on a straight track. The frequency of this horn appears to be $680 \ Hz$ to the car driver. If the velocity of sound in air is $340 \ m/s$, then the velocity of the approaching bus is: (in $m/s$)

$A$ person is observing two trains,one coming towards him and the other leaving with the same speed $4\, m/s$. If their whistling frequencies are $240\, Hz$ each,then the number of beats per second heard by the person will be: (if the velocity of sound is $320\, m/s$)

$A$ whistle revolves in a circle with an angular speed of $20 \; rad/s$ using a string of length $50 \; cm.$ If the frequency of sound from the whistle is $385 \; Hz,$ then what is the minimum frequency heard by an observer,who is far away from the centre in the same plane? $(v = 340 \; m/s)$

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