$A$ source and an observer move away from each other with the same velocity of $10 \,ms^{-1}$ with respect to the ground. If the observer finds the frequency of sound coming from the source as $1980 \,Hz$, then the actual frequency of the source is (speed of sound in air $= 340 \,ms^{-1}$). (in $\,Hz$)
- A$1950$
- B$2100$
- C$2132$
- D$2486$
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Similar Questions
$A$ train blowing its whistle moves with constant speed on a straight track towards an observer and then crosses him. If the ratio of the difference between the actual and apparent frequencies is $3:2$ in the two cases (approaching and receding),then the speed of the train is (where $v$ is the speed of sound).
Medium
View SolutionMatch Column-$A$ with Column-$B$.
Column-$A$ Column-$B$ $(a)$ When source of sound and listener move towards wall. $(i)$ Listener would hear a sound with same frequency as that of source. $(b)$ When source of sound and listener move away from each other. $(ii)$ Listener would hear a sound with frequency smaller than that of source. $(iii)$ Frequency of echo would be greater than that of source.
| Column-$A$ | Column-$B$ |
| $(a)$ When source of sound and listener move towards wall. | $(i)$ Listener would hear a sound with same frequency as that of source. |
| $(b)$ When source of sound and listener move away from each other. | $(ii)$ Listener would hear a sound with frequency smaller than that of source. |
| $(iii)$ Frequency of echo would be greater than that of source. |
Easy
View Solution$A$ source producing sound of frequency $170 \, Hz$ is approaching a stationary observer with a velocity $17 \, ms^{-1}$. The apparent change in the wavelength of sound heard by the observer is (speed of sound in air $= 340 \, ms^{-1}$) ..... $m$
Medium
View SolutionTwo sirens situated one kilometer apart are producing sound of frequency $330 \ Hz$. An observer starts moving from one siren to the other with a speed of $2 \ m/s$. If the speed of sound is $330 \ m/s$,what will be the beat frequency heard by the observer?
Difficult
View SolutionWhen the observer moves towards a stationary source with velocity $V_1$,the apparent frequency of the emitted note is $F_1$. When the observer moves away from the source with velocity $V_1$,the apparent frequency is $F_2$. If $V$ is the velocity of sound in air and $F_1 / F_2 = 2$,then $V / V_1$ is equal to:
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