L xrightarrow[(ii) H_3O^{oplus}]{(i) PhMgBr} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The final product is $Ph_2C=CH_2$ ($1$, $1$-diphenylethene). The last step is a Wittig reaction: $N + Ph_3P=CH_2 \rightarrow Ph_2C=CH_2$. This imp

Vedclass · Accepted Answer

Benzaldehyde

Vedclass · Answer

(A) The final product is $Ph_2C=CH_2$ ($1$, $1$-diphenylethene). The last step is a Wittig reaction: $N + Ph_3P=CH_2 \rightarrow Ph_2C=CH_2$. This implies $N$ must be benzophenone $(Ph_2C=O)$. The step $M \xrightarrow{CrO_3 / H^{\oplus}} N$ is an oxidation of a secondary alcohol to a ketone. Thus, $M$ is diphenylmethanol $(Ph_2CHOH)$. The first step is the Grignard reaction: $L \xrightarrow[(ii) H_3O^{\oplus}]{(i) PhMgBr} Ph_2CHOH$. Benzaldehyde $(PhCHO)$ reacts with $PhMgBr$ followed by hydrolysis to give diphenylmethanol $(Ph_2CHOH)$. Therefore, $L$ is benzaldehyde.

$L$ $\xrightarrow[(ii) H_3O^{\oplus}]{(i) PhMgBr} M$ $\xrightarrow{CrO_3 / H^{\oplus}} N$ $\xrightarrow{Ph_3P=CH_2} Ph_2C=CH_2$
$L$ in the above sequence of reaction is/are (where $L \neq M \neq N$)

Similar Questions

Conversion of benzene to acetophenone can be brought about by

Which among the following reagents is used in the Rosenmund reduction?

The molecular formula of the final product of the following synthetic scheme is:

$Ethyl \ methyl \ ketone$ is obtained by heating calcium salts of

Ketones are prepared by

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$L$ $\xrightarrow[(ii) H_3O^{\oplus}]{(i) PhMgBr} M$ $\xrightarrow{CrO_3 / H^{\oplus}} N$ $\xrightarrow{Ph_3P=CH_2} Ph_2C=CH_2$ $L$ in the above sequence of reaction is/are (where $L \neq M \neq N$)