$Li$ occupies a higher position in the electrochemical series of metals as compared to $Cu$ since:
- Athe standard reduction potential of $Li^{+} / Li$ is lower than that of $Cu^{2+} / Cu$
- Bthe standard reduction potential of $Cu^{2+} / Cu$ is lower than that of $Li^{+} / Li$
- Cthe standard oxidation potential of $Li / Li^{+}$ is lower than that of $Cu / Cu^{2+}$
- D$Li$ is smaller in size as compared to $Cu$
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Similar Questions
The standard electrode potentials of $Zn^{2+}/Zn$ and $Ag^{+}/Ag$ are $-0.763 \ V$ and $+0.799 \ V$ respectively. The standard potential of the cell is ............ $V$.
Easy
View SolutionElectrode potential data are given below :
$Fe^{3+}_{(aq)} + e^- \to Fe^{2+}_{(aq)}; \, E^o = +0.77 \, V$
$Al^{3+}_{(aq)} + 3e^- \to Al_{(s)}; \, E^o = -1.66 \, V$
$Br_{2(aq)} + 2e^- \to 2Br^{-}_{(aq)}; \, E^o = +1.08 \, V$
Based on the data given above,the reducing power of $Fe^{2+}$,$Al$ and $Br^{-}$ will increase in the order:
$Fe^{3+}_{(aq)} + e^- \to Fe^{2+}_{(aq)}; \, E^o = +0.77 \, V$
$Al^{3+}_{(aq)} + 3e^- \to Al_{(s)}; \, E^o = -1.66 \, V$
$Br_{2(aq)} + 2e^- \to 2Br^{-}_{(aq)}; \, E^o = +1.08 \, V$
Based on the data given above,the reducing power of $Fe^{2+}$,$Al$ and $Br^{-}$ will increase in the order:
Easy
View SolutionThe standard electrode potential $(E^o)$ of $Cu^{2+}/Cu$ is $+0.34 \, V$,while that of $Zn^{2+}/Zn$ is $-0.76 \, V$. Explain the reason for this difference.
Medium
View SolutionWhat is the value of the standard electrode potential of a standard hydrogen electrode $(SHE)$ (in $V$)?
Easy
View SolutionThe reducing ability of the metals $K$,$Au$,$Zn$ and $Pb$ follows the order
MediumKVPY 2017
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