$PbCl_{2}$ is insoluble in cold water. Addition of $HCl$ increases its solubility due to

  • A
    formation of soluble complex anions like $[PbCl_{3}]^{-}$
  • B
    oxidation of $Pb(II)$ to $Pb(IV)$
  • C
    formation of $[Pb(H_{2}O)_{6}]^{2+}$
  • D
    formation of polymeric lead complexes

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Similar Questions

Given below are two statements:
Statement $I$ : $N(CH_3)_3$ and $P(CH_3)_3$ can act as ligands to form transition metal complexes.
Statement $II$: As $N$ and $P$ are from same group,the nature of bonding of $N(CH_3)_3$ and $P(CH_3)_3$ is always same with transition metals.
In the light of the above statements,choose the most appropriate answer from the options given below:

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