$A$ Zener diode having a breakdown voltage of $5.6 \ V$ is connected in reverse bias with a battery of emf $10 \ V$ and a resistance of $100 \ \Omega$ in series. The current flowing through the Zener diode is (in $mA$)

What is the value of output voltage $V_0$ in $V$ for the circuit shown in the figure?

The circuit shown below is working as an $8\; V\; dc$ regulated voltage source. When $12 \; V$ is used as input, the power dissipated (in $mW$) in each diode is (considering both zener diodes are identical).

In a Zener regulated power supply, a Zener diode with $V_z = 6 \, V$ is used for regulation. The load current is $4 \, mA$ and the unregulated input voltage is $10 \, V$. To get a Zener current five times the load current, the value of the series resistor $R_S$ is nearly:

In the following circuit,the reading of the ammeter will be (Take Zener breakdown voltage $= 4 \ V$) (in $mA$)

The value of power dissipated across the Zener diode $(V_{Z} = 15 \text{ V})$ connected in the circuit as shown in the figure is $x \times 10^{-1} \text{ watt}$. The value of $x$, to the nearest integer, is ..............