mathop {lim }limits_{x to 0} frac{{{x^2} - ta | vedclass

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Question

(B) We need to evaluate the limit: $\mathop {\lim }\limits_{x 	o 0} \frac{{{x^2} - 	an 2x}}{{	an x}}$.Dividing the numerator and denominator by $x$

Vedclass · Accepted Answer

$-2$

Vedclass · Answer

(B) We need to evaluate the limit: $\mathop {\lim }\limits_{x 	o 0} \frac{{{x^2} - 	an 2x}}{{	an x}}$.Dividing the numerator and denominator by $x$,we get:$\mathop {\lim }\limits_{x 	o 0} \frac{\frac{x^2}{x} - \frac{	an 2x}{x}}{\frac{	an x}{x}} = \mathop {\lim }\limits_{x 	o 0} \frac{x - 2 \cdot \frac{	an 2x}{2x}}{\frac{	an x}{x}}$.Using the standard limit $\mathop {\lim }\limits_{	heta 	o 0} \frac{	an 	heta}{	heta} = 1$,we have:$\frac{0 - 2(1)}{1} = -2$.

$\mathop {\lim }\limits_{x \to 0} \frac{{{x^2} - \tan 2x}}{{\tan x}} = $

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