A car is moving with a speed of 72 text{ km/h | vedclass

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(C) According to the Doppler effect, when an observer moves with velocity $v_0$ towards a stationary source, the observed frequency $N_{	ext{approach

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$100$

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(C) According to the Doppler effect, when an observer moves with velocity $v_0$ towards a stationary source, the observed frequency $N_{	ext{approach}}$ is given by:$N_{	ext{approach}} = N \left( \frac{v + v_0}{v} ight)$Given $N = 850 	ext{ Hz}$, $v = 340 	ext{ m/s}$, and $v_0 = 72 	ext{ km/h} = 72 	imes \frac{5}{18} = 20 	ext{ m/s}$.$N_{	ext{approach}} = 850 \left( \frac{340 + 20}{340} ight) = 850 \left( \frac{360}{340} ight) = 900 	ext{ Hz}$.When the observer moves away from the source, the observed frequency $N_{	ext{separation}}$ is given by:$N_{	ext{separation}} = N \left( \frac{v - v_0}{v} ight)$$N_{	ext{separation}} = 850 \left( \frac{340 - 20}{340} ight) = 850 \left( \frac{320}{340} ight) = 800 	ext{ Hz}$.The difference between the two frequencies is:$\Delta N = N_{	ext{approach}} - N_{	ext{separation}} = 900 	ext{ Hz} - 800 	ext{ Hz} = 100 	ext{ Hz}$.

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