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(D) The molecular formula $C_6H_7N$ and the given reactions indicate that $x$ is Aniline $(C_6H_5NH_2)$.$1$. $x$ is a primary amine because it gives t

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$7$

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(D) The molecular formula $C_6H_7N$ and the given reactions indicate that $x$ is Aniline $(C_6H_5NH_2)$.$1$. $x$ is a primary amine because it gives the carbylamine test (unpleasant smell of $y$, which is phenyl isocyanide, $C_6H_5NC$).$2$. Reaction with benzenesulphonyl chloride (Hinsberg reagent): $C_6H_5NH_2 + C_6H_5SO_2Cl \rightarrow C_6H_5-SO_2-NH-C_6H_5$ $(z)$.$3$. Compound $z$ is $N$-phenylbenzenesulfonamide.$4$. Different types of $H$ atoms in $z$:- Ring $1$ (attached to $SO_2$): $3$ types (ortho, meta, para).- Ring $2$ (attached to $NH$): $3$ types (ortho, meta, para).- $H$ atom on Nitrogen: $1$ type.Total different $H$ atoms = $3 + 3 + 1 = 7$.

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