A cup of water at 5^{circ}C (system) is place | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The process involves heating water from $5^{\circ}C$ to $100^{\circ}C$ and then converting it into steam: $H_2O(\ell)_{5^{\circ}C} \longrightarrow

Vedclass · Accepted Answer

$q = +ve, w = -ve, \Delta U = +ve$

Vedclass · Answer

(B) The process involves heating water from $5^{\circ}C$ to $100^{\circ}C$ and then converting it into steam: $H_2O(\ell)_{5^{\circ}C} \longrightarrow H_2O(\ell)_{100^{\circ}C} \rightleftharpoons H_2O(g)_{100^{\circ}C}$.Since heat is absorbed by the system from the microwave, $q = +ve$.As the water expands during boiling against the external pressure, the system does work on the surroundings, so $w = -ve$.The internal energy of the system increases because the temperature rises and the phase changes from liquid to gas, which has higher potential energy, thus $\Delta U = +ve$.

$A$ cup of water at $5^{\circ}C$ (system) is placed in a microwave oven and the oven is turned on for one minute, during which the water begins to boil. Which of the following options is true?

Similar Questions

What is the internal energy change when $62 \ J$ of work is done on the system and $128 \ J$ of heat is transferred to the surrounding (in $J$)?

When a system is supplied with $60 \ J$ of heat,it performs $15 \ J$ of work. The change in the internal energy of the system is ......... $J$.

When a system expands under adiabatic conditions,what happens to its internal energy?

If $1 \ L$ of an ideal gas at a pressure of $20 \ atm$ expands isothermally and reversibly to a final volume of '$X$' $L$ by absorbing $92.12 \ L \ atm$ heat,'$X$' (in $L$) is

$A$ system is provided $50 \text{ J}$ of heat and work done on the system is $10 \text{ J}$. What is the change in internal energy (in $\text{ J}$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module