Difficult
$A$ student has been given $0.314 \ g$ of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained $0.4813 \ g$ of barium sulphate. The percentage of sulphur present in the compound is . . . . . .
(Given Molar mass in $g \ mol^{-1}$: $S = 32$, $BaSO_4 = 233$) (in $\%$)
(Given Molar mass in $g \ mol^{-1}$: $S = 32$, $BaSO_4 = 233$) (in $\%$)
- A$42.10$
- B$63.15$
- C$21.05$
- D$48.24$
Explore More
Similar Questions
In phosphorus estimation,$0.31 \ g$ of an organic compound gave $0.444 \ g$ of magnesium pyrophosphate (molar mass $= 222 \ g \ mol^{-1}$). The percentage of phosphorus in the compound is
Which method is used for the estimation of nitrogen in an organic compound?
Easy
View SolutionIn the Carius method,$0.099 \, g$ of an organic compound gave $0.287 \, g$ of $AgCl$. The percentage of chlorine in the compound is:
Medium
View SolutionIn Dumas' method of estimation of nitrogen,$0.35 \ g$ of an organic compound gave $55 \ mL$ of nitrogen collected at $300 \ K$ temperature and $715 \ mm$ pressure. The percentage composition of nitrogen in the compound would be (aqueous tension at $300 \ K = 15 \ mm$). (in $\%$)
DifficultAIPMT 2011
View Solution$0.2595 \ g$ of an organic substance in a quantitative analysis yielded $0.35 \ g$ of barium sulphate. The percentage of sulphur in the substance is $...$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo