$Ph-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} \text{Product}$
Consider the above reaction:
$A$. The reaction proceeds through a more stable radical intermediate.
$B$. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).
$C$. During this reaction, benzene is formed as a byproduct.
$D$. $1-\text{Bromo}-2-\text{phenylethane}$ is formed as the minor product.
$E$. The same reaction in the absence of peroxide proceeds via a carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:

• A
  $A$ & $E$ Only
• B
  $A, B$ & $D$ Only
• C
  $C, D$ & $E$ Only
• D
  $A, C$ & $E$ Only