RMgI when treated with ice-cold water liberat | vedclass

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(C) $1$. Reaction with water: $RMgI + H_2O ightarrow RH + Mg(OH)I$. The gas produced is an alkane $RH$.$2$. Molar mass calculation: At $STP$, $1 	e

Vedclass · Accepted Answer

$30$

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(C) $1$. Reaction with water: $RMgI + H_2O ightarrow RH + Mg(OH)I$. The gas produced is an alkane $RH$.$2$. Molar mass calculation: At $STP$, $1 	ext{ mole}$ of gas occupies $22.4 	ext{ dm}^3$. Given density is $1.4 	ext{ dm}^3/	ext{g}$, so molar mass $M = 22.4 / 1.4 = 16 	ext{ g/mol}$.$3$. Identification: The alkane with molar mass $16 	ext{ g/mol}$ is methane $(CH_4)$.$4$. Reaction with iodine: $CH_4 + I_2 \xrightarrow{HIO_3} CH_3I (X) + HI$.$5$. Wurtz reaction: $2CH_3I + 2Na \xrightarrow{	ext{dry ether}} C_2H_6 (Y) + 2NaI$.$6$. Molar mass of $(Y)$ $(C_2H_6)$: $(2 	imes 12) + (6 	imes 1) = 30 	ext{ g/mol}$.

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