A liquid of density 600 text{ kg/m}^3 is flow | vedclass

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(D) Given: Density $ho = 600 	ext{ kg/m}^3$, Area $A_A = 1.0 	ext{ cm}^2 = 100 	ext{ mm}^2$, Area $A_B = 20 	ext{ mm}^2$, Velocity $v_A = 10 	e

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(D) Given: Density $ho = 600 	ext{ kg/m}^3$, Area $A_A = 1.0 	ext{ cm}^2 = 100 	ext{ mm}^2$, Area $A_B = 20 	ext{ mm}^2$, Velocity $v_A = 10 	ext{ cm/s} = 0.1 	ext{ m/s}$.Using the equation of continuity, $A_A v_A = A_B v_B$.$100 	imes 0.1 = 20 	imes v_B \Rightarrow v_B = 0.5 	ext{ m/s}$.Applying Bernoulli's equation for a horizontal pipe $(h_A = h_B)$:$P_A + \frac{1}{2} ho v_A^2 = P_B + \frac{1}{2} ho v_B^2$.The pressure difference is $P_A - P_B = \frac{1}{2} ho (v_B^2 - v_A^2)$.Substituting the values: $P_A - P_B = \frac{1}{2} 	imes 600 	imes (0.5^2 - 0.1^2) = 300 	imes (0.25 - 0.01) = 300 	imes 0.24 = 72 	ext{ Pa}$.

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