(B) Using the ideal gas equation: $PV = \mu RT$.Since the temperature $T$ is constant,we have $PV \propto \mu$,which implies $\frac{P_1 V_1}{\mu_1} =

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) Using the ideal gas equation: $PV = \mu RT$.Since the temperature $T$ is constant,we have $PV \propto \mu$,which implies $\frac{P_1 V_1}{\mu_1} = \frac{P_2 V_2}{\mu_2}$.Given:$P_1 = 50\, mm$,$V_1 = 100\, ml$,$\mu_1 = 1\, mole$.$P_2 = 100\, mm$,$\mu_2 = 2\, moles$,$V_2 = ?$.Substituting the values into the equation:$\frac{50 \times 100}{1} = \frac{100 \times V_2}{2}$.$5000 = 50 \times V_2$.$V_2 = \frac{5000}{50} = 100\, ml$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Medium

$1$ mole of gas occupies a volume of $100\, ml$ at $50\, mm$ pressure. What is the volume occupied by two moles of gas at $100\, mm$ pressure and at the same temperature? (in $ml$)

A
$50$
B
$100$
C
$200$
D
$500$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Kinetic Theory of Gases

Subtopic

Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Column-$I$ represents gas laws and Column-$II$ represents the physical quantity which is constant for the given law. Match them correctly:

Column-$I$ Column-$II$

$(a)$ Boyle's law $(i)$ Pressure

$(b)$ Charles's law $(ii)$ Volume

$(iii)$ Temperature

Column-$I$	Column-$II$
$(a)$ Boyle's law	$(i)$ Pressure
$(b)$ Charles's law	$(ii)$ Volume
	$(iii)$ Temperature

Easy

View Solution

The gas equation $\frac{PV}{T} = \text{constant}$ is true for a constant mass of an ideal gas undergoing:

Medium

View Solution

$A$ perfect gas at $27^{\circ}C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be ...... $^{\circ}C$.

Medium

View Solution

$A$ perfect gas at $27^{\circ} C$ is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be (in $^{\circ} C$)

EasyKCET 2011

View Solution

The equation of state corresponding to $8 \, g$ of $O_2$ is:

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$1$ mole of gas occupies a volume of $100\, ml$ at $50\, mm$ pressure. What is the volume occupied by two moles of gas at $100\, mm$ pressure and at the same temperature? (in $ml$)

Similar Questions

Column-$I$ represents gas laws and Column-$II$ represents the physical quantity which is constant for the given law. Match them correctly: Column-$I$ Column-$II$ $(a)$ Boyle's law $(i)$ Pressure $(b)$ Charles's law $(ii)$ Volume $(iii)$ Temperature

The gas equation $\frac{PV}{T} = \text{constant}$ is true for a constant mass of an ideal gas undergoing:

$A$ perfect gas at $27^{\circ}C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be ...... $^{\circ}C$.

$A$ perfect gas at $27^{\circ} C$ is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be (in $^{\circ} C$)

The equation of state corresponding to $8 \, g$ of $O_2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Column-$I$ represents gas laws and Column-$II$ represents the physical quantity which is constant for the given law. Match them correctly:

Column-$I$ Column-$II$

$(a)$ Boyle's law $(i)$ Pressure

$(b)$ Charles's law $(ii)$ Volume

$(iii)$ Temperature